Difference between revisions of "2006 AMC 12B Problems/Problem 4"
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== Solution == | == Solution == | ||
| − | The total price of the items is <math>(8-.01)+(5-.01)+(3-.01)+(2-.01)+(1-.01)=19-.05=18. | + | The total price of the items is <math>(8-.01)+(5-.01)+(3-.01)+(2-.01)+(1-.01)=19-.05=18.95</math> |
| − | <math>20-18.05= | + | <math>20-18.95=1.05</math> |
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| + | <math>\frac{1.05}{20}=.0525 \Rightarrow \text{(A)}</math> | ||
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== See also == | == See also == | ||
{{AMC12 box|year=2006|ab=B|num-b=3|num-a=5}} | {{AMC12 box|year=2006|ab=B|num-b=3|num-a=5}} | ||
Revision as of 11:03, 3 December 2007
Problem
Mary is about to pay for five items at the grocery store. The prices of the items are 
, 
, 
, 
, and 
. Mary will pay with a twenty-dollar bill. Which of the following is closest to the percentage of the 
that she will receive in change?
Solution
The total price of the items is 
See also
| 2006 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by Problem 3 |
Followed by Problem 5 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
