Difference between revisions of "2006 AMC 12B Problems/Problem 6"

 
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== Solution ==
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==Solution==
There are <math>25+386=411</math> calories in <math>600</math> grams of lemonade. There are <math>\frac{411}{3}=137\Rightarrow \text{(B)}</math> calories in <math>200</math> grams of lemonade.
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Francesca makes a total of <math>100+100+400=600</math> grams of lemonade, and in those <math>600</math> grams, there are <math>25</math> calories from the lemon juice and <math>386</math> calories from the sugar, for a total of <math>25+386=411</math> calories per <math>600</math> grams. We want to know how many calories there are in <math>200=600/3</math> grams, so we just divide <math>411</math> by <math>3</math> to get <math>137\implies\boxed{(\text{B})}</math>.
 
 
  
 
== See also ==
 
== See also ==
* [[2006 AMC 12B Problems]]
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{{AMC12 box|year=2006|ab=B|num-b=5|num-a=7}}
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{{MAA Notice}}

Latest revision as of 13:57, 4 December 2015

Problem

Francesca uses 100 grams of lemon juice, 100 grams of sugar, and 400 grams of water to make lemonade. There are 25 calories in 100 grams of lemon juice and 386 calories in 100 grams of sugar. Water contains no calories. How many calories are in 200 grams of her lemonade?

$\text {(A) } 129 \qquad \text {(B) } 137 \qquad \text {(C) } 174 \qquad \text {(D) } 223 \qquad \text {(E) } 411$

Solution

Francesca makes a total of $100+100+400=600$ grams of lemonade, and in those $600$ grams, there are $25$ calories from the lemon juice and $386$ calories from the sugar, for a total of $25+386=411$ calories per $600$ grams. We want to know how many calories there are in $200=600/3$ grams, so we just divide $411$ by $3$ to get $137\implies\boxed{(\text{B})}$.

See also

2006 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

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