Difference between revisions of "2006 AMC 8 Problems/Problem 24"
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In the multiplication problem below <math>A</math>, <math>B</math>, <math>C</math>, <math>D</math> and are different digits. What is <math>A+B</math>? | In the multiplication problem below <math>A</math>, <math>B</math>, <math>C</math>, <math>D</math> and are different digits. What is <math>A+B</math>? | ||
− | <cmath> \begin{ | + | <cmath> \begin{array}{cccc}& A & B & A\\ \times & & C & D\\ \hline C & D & C & D\\ \end{array} </cmath> |
<math> \textbf{(A)}\ 1\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 3\qquad\textbf{(D)}\ 4\qquad\textbf{(E)}\ 9 </math> | <math> \textbf{(A)}\ 1\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 3\qquad\textbf{(D)}\ 4\qquad\textbf{(E)}\ 9 </math> |
Revision as of 20:05, 10 March 2015
Problem
In the multiplication problem below , , , and are different digits. What is ?
Solution
, so . Therefore, and , so .
See Also
2006 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 23 |
Followed by Problem 25 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |
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