Difference between revisions of "2006 Cyprus MO/Lyceum/Problem 8"

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==Problem==
 
==Problem==
<div style="float:right">
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[[Image:2006 CyMO-8.PNG|250px|right]]
[[Image:2006 CyMO-8.PNG|250px]]
 
</div>
 
  
 
In the figure <math>AB\Gamma \Delta E</math> is a regular 5-sided polygon and <math>Z</math>, <math>H</math>, <math>\Theta</math>, <math>I</math>, <math>K</math> are the points of intersections of the extensions of the sides.
 
In the figure <math>AB\Gamma \Delta E</math> is a regular 5-sided polygon and <math>Z</math>, <math>H</math>, <math>\Theta</math>, <math>I</math>, <math>K</math> are the points of intersections of the extensions of the sides.
 
If the area of the "star" <math>AHB\Theta \Gamma I\Delta KEZA</math> is 1, then the area of the shaded quadrilateral <math>A\Gamma IZ</math> is
 
If the area of the "star" <math>AHB\Theta \Gamma I\Delta KEZA</math> is 1, then the area of the shaded quadrilateral <math>A\Gamma IZ</math> is
  
A. <math>\frac{2}{3}</math>
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<math>\mathrm{(A)}\ \frac{2}{3}\qquad\mathrm{(B)}\ \frac{1}{2}\qquad\mathrm{(C)}\ \frac{3}{7}\qquad\mathrm{(D)}\ \frac{3}{10}\qquad\mathrm{(E)}\ \text{None of these}</math>
 
 
B. <math>\frac{1}{2}</math>
 
 
 
C. <math>\frac{3}{7}</math>
 
 
 
D. <math>\frac{3}{10}</math>
 
 
 
E. None of these
 
  
 
==Solution==
 
==Solution==

Revision as of 10:41, 27 April 2008

Problem

2006 CyMO-8.PNG

In the figure $AB\Gamma \Delta E$ is a regular 5-sided polygon and $Z$, $H$, $\Theta$, $I$, $K$ are the points of intersections of the extensions of the sides. If the area of the "star" $AHB\Theta \Gamma I\Delta KEZA$ is 1, then the area of the shaded quadrilateral $A\Gamma IZ$ is

$\mathrm{(A)}\ \frac{2}{3}\qquad\mathrm{(B)}\ \frac{1}{2}\qquad\mathrm{(C)}\ \frac{3}{7}\qquad\mathrm{(D)}\ \frac{3}{10}\qquad\mathrm{(E)}\ \text{None of these}$

Solution

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See also

2006 Cyprus MO, Lyceum (Problems)
Preceded by
Problem 7
Followed by
Problem 9
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