2007 AMC 10A Problems/Problem 4

Revision as of 15:27, 6 January 2008 by Azjps (talk | contribs) (solution)
(diff) ← Older revision | Latest revision (diff) | Newer revision → (diff)

Problem

The larger of two consecutive odd integers is three times the smaller. What is their sum?

$\text{(A)}\ 4 \qquad \text{(B)}\ 8 \qquad \text{(C)}\ 12 \qquad \text{(D)}\ 16 \qquad \text{(E)}\ 20$

Solution

Let the two consecutive odd integers be $a$, $a+2$. Then $a+2 = 3a$, so $a = 1$ and their sum is $4\ \mathrm{(B)}$.

See also

{{AMC10 box|year=2007|ab=A|num-b=3|num-a=5}