Difference between revisions of "2007 AMC 12B Problems/Problem 10"

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So, there are 8 girls, <math>\Rightarrow \fbox{C}</math>
 
So, there are 8 girls, <math>\Rightarrow \fbox{C}</math>
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==See Also==
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{{AMC12 box|year=2007|ab=B|num-b=9|num-a=11}}

Revision as of 02:20, 10 February 2009

Problem

Some boys and girls are having a car wash to raise money for a class trip to China. Initially $40$% of the group are girls. Shortly thereafter two girls leave and two boys arrive, and then $30$% of the group are girls. How many girls were initially in the group?

$\mathrm {(A)} 4$ $\mathrm {(B)} 6$ $\mathrm {(C)} 8$ $\mathrm {(D)} 10$ $\mathrm {(E)} 12$

Solution

First, determine the total number of people in the group.

$2=(40/100-30/100)t$

$t=200/10=20$

Now find the original number of girls:

$40/100t = 800/100 = 8$

So, there are 8 girls, $\Rightarrow \fbox{C}$

See Also

2007 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions