Difference between revisions of "2007 AMC 12B Problems/Problem 3"

Revision as of 10:50, 4 July 2013

Problem

The point $O$ is the center of the circle circumscribed about triangle $ABC$ , with $\angle BOC = 120^{\circ}$ and $\angle AOB = 140^{\circ}$ , as shown. What is the degree measure of $\angle ABC$ ?

$\mathrm {(A)} 35 \qquad \mathrm {(B)} 40 \qquad \mathrm {(C)} 45 \qquad \mathrm {(D)} 50 \qquad \mathrm {(E)} 60$

Solution

$\angle AOC=360-140-120=100=2\angle ABC$

$\angle ABC=50 \Rightarrow \mathrm {D}$

2007 AMC 12B (Problems • Answer Key • Resources)
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Difference between revisions of "2007 AMC 12B Problems/Problem 3"

Revision as of 10:50, 4 July 2013

Problem

Solution

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