Difference between revisions of "2007 AMC 8 Problems/Problem 4"

(See Also)
(Solution)
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by a different window.
 
by a different window.
  
Our answer is <math>30</math>, <math>\boxed{D}</math>
+
Therefore, we have <math> \boxed{\textbf{(D)}\ 30} </math> ways.
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==See Also==
 
==See Also==
 
{{AMC8 box|year=2007|num-b=3|num-a=5}}
 
{{AMC8 box|year=2007|num-b=3|num-a=5}}

Revision as of 13:11, 9 December 2012

Problem

A haunted house has six windows. In how many ways can Georgie the Ghost enter the house by one window and leave by a different window?

$\mathrm{(A)}\ 12 \qquad\mathrm{(B)}\ 15 \qquad\mathrm{(C)}\ 18 \qquad\mathrm{(D)}\ 30 \qquad\mathrm{(E)}\ 36$

Solution

Georgie can enter the haunted house through any of the six windows. Then, he can leave through any of the remaining five windows.

So, Georgie has a total of $6 * 5$ ways he can enter the house by one window and leave by a different window.

Therefore, we have $\boxed{\textbf{(D)}\ 30}$ ways.

See Also

2007 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions