Difference between revisions of "2007 Alabama ARML TST Problems/Problem 5"

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==Problem==
 
==Problem==
How many positive 5-digit odd integers are palindromes?
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How many positive 5-digit odd integers are [[palindrome]]s?
  
 
==Solution==
 
==Solution==
The units digit must be odd, and the ten-thousands digit must be equal to the units digit. So there are 5 possible choices there. Then there are ten choices for the tens and hundreds digits, but the thousands digit is fixed. Therefore there are 5*20*20=500 5-digit odd palindromes.
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The units digit must be odd, and the ten-thousands digit must be equal to the units digit. So there are 5 possible choices there. Then there are ten choices for the tens and hundreds digits, but the thousands digit is fixed. Therefore there are <math>5 \cdot 10 \cdot 10=\boxed{500}</math> 5-digit odd palindromes.
  
 
==See also==
 
==See also==

Latest revision as of 09:16, 18 June 2008

Problem

How many positive 5-digit odd integers are palindromes?

Solution

The units digit must be odd, and the ten-thousands digit must be equal to the units digit. So there are 5 possible choices there. Then there are ten choices for the tens and hundreds digits, but the thousands digit is fixed. Therefore there are $5 \cdot 10 \cdot 10=\boxed{500}$ 5-digit odd palindromes.

See also

2007 Alabama ARML TST (Problems)
Preceded by:
Problem 4
Followed by:
Problem 6
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