Difference between revisions of "2008 AIME I Problems/Problem 1"

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== Problem ==
 
== Problem ==
Of the students attending a school party, <math>60</math>% of the students are girls, and <math>40</math>% of the students like to dance. After these students are joined by <math>20</math> more boy students, all of whom like to dance, the party is now <math>58</math>% girls. How many students now at the party like to dance?
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Of the students attending a school party, <math>60\%</math> of the students are girls, and <math>40\%</math> of the students like to dance. After these students are joined by <math>20</math> more boy students, all of whom like to dance, the party is now <math>58\%</math> girls. How many students now at the party like to dance?
  
 
== Solution ==
 
== Solution ==

Revision as of 14:28, 19 April 2008

Problem

Of the students attending a school party, $60\%$ of the students are girls, and $40\%$ of the students like to dance. After these students are joined by $20$ more boy students, all of whom like to dance, the party is now $58\%$ girls. How many students now at the party like to dance?

Solution

Say that there were $3k$ girls and $2k$ boys at the party originally. $2k$ like to dance. Then, there are $3k$ girls and $2k + 20$ boys, and $2k + 20$ like to dance.

Thus, $\dfrac{3k}{5k + 20} = \dfrac{29}{50}$, solving gives $k = 116$. Thus, the number of people that like to dance is $2k + 20 = \boxed{252}$.

See also

2008 AIME I (ProblemsAnswer KeyResources)
Preceded by
First question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
All AIME Problems and Solutions