Difference between revisions of "2008 AMC 10A Problems/Problem 8"

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==Problem==
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#redirect [[2008 AMC 12A Problems/Problem 6]]
Heather compares the price of a new computer at two different stores. Store <math>A</math> offers <math>15\%</math> off the sticker price followed by a <math>\</math><math>90</math> rebate, and store <math>B</math> offers <math>25\%</math> off the same sticker price with no rebate. Heather saves <math>\</math><math>15</math> by buying the computer at store <math>A</math> instead of store <math>B</math>. What is the sticker price of the computer, in dollars?
 
 
 
<math>\mathrm{(A)}\ 750\qquad\mathrm{(B)}\ 900\qquad\mathrm{(D)}\ 1000\qquad\mathrm{(D)}\ 1050\qquad\mathrm{(E)}\ 1500</math>
 
 
 
==Solution==
 
Let the sticker price be <math>x</math>.
 
 
 
The price of the computer is <math>0.85x-90</math> at store <math>A</math>, and <math>0.75x</math> at store <math>B</math>.
 
 
 
Heather saves <math>\</math><math>15</math> at store <math>A</math>, so <math>0.85x-90+15=0.75x</math>.
 
 
 
Solving, we find <math>x=750</math>, and the thus answer is <math>\mathrm{(A)}</math>.
 
 
 
==See also==
 
{{AMC10 box|year=2008|ab=A|num-b=7|num-a=9}}
 

Latest revision as of 23:37, 25 April 2008

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