# Difference between revisions of "2008 AMC 10B Problems/Problem 11"

## Problem

Postman Pete has a pedometer to count his steps. The pedometer records up to 99999 steps, then flips over to 00000 on the next step. Pete plans to determine his mileae for a year. On January 1 Pete sets the pedometer to 00000. During the year, the pedometer flips from 99999 to 00000 forty-four times. On December 31 the pedometer reads 50000. Pete takes 1800 steps per mile. Which of the following is closest to the number of miles Pete walked during the year?

(A) 2500 (B) 3000 (C) 3500 (D) 4000 (E) 4500

## Problem

{{Suppose that $(u_n)$ is a serquence of real numbers satifying $u_{n+2}=2u_{n+1}+u_n$,

and that $u_3=9$ and $u_6=128$. What is $u_5$?

(A) 40 (B) 53 (C) 68 (D) 88 (E) 104}}

## Solution

Every time the pedometer flips from $99999$ to

$00000$ Pete has walked $100000$ steps.

So, if the pedometer flipped $44$ times

Pete walked $44*100000+50000=4450000$ steps.

Dividing by $1800$ gives $2472.\overline{2}$

This is closest to answer $\boxed{A}$.