Difference between revisions of "2008 AMC 8 Problems/Problem 18"
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==Solution== | ==Solution== | ||
+ | We will deal with this part by part: | ||
+ | Part 1: 1/4 circumference of big circle= <math>\frac{2\pi r}{4}=\frac{\pi r}{2}=\frac{20\pi}{2}=10\pi</math> | ||
+ | Part 2: Big radius minus small radius= <math>20-10=10</math> | ||
+ | Part 3: 1/4 circumference of small circle= <math>\frac{\pi r}{2}=\frac{10\pi}{2}=5\pi</math> | ||
+ | Part 4: Diameter of small circle: <math>2*10=20</math> | ||
+ | Part 5: Same as part 3: <math>5\pi</math> | ||
+ | Part 6: Same as part 2: <math>10</math> | ||
+ | Total: <math>10\pi + 10 + 5\pi + 20 + 5\pi + 10 = 20\pi + 40</math> '''E''' | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2008|num-b=17|num-a=19}} | {{AMC8 box|year=2008|num-b=17|num-a=19}} |
Revision as of 14:37, 11 December 2012
Problem
Two circles that share the same center have radii meters and meters. An aardvark runs along the path shown, starting at and ending at . How many meters does the aardvark run?
Solution
We will deal with this part by part: Part 1: 1/4 circumference of big circle= Part 2: Big radius minus small radius= Part 3: 1/4 circumference of small circle= Part 4: Diameter of small circle: Part 5: Same as part 3: Part 6: Same as part 2: Total: E
See Also
2008 AMC 8 (Problems • Answer Key • Resources) | ||
Preceded by Problem 17 |
Followed by Problem 19 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AJHSME/AMC 8 Problems and Solutions |