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Difference between revisions of "2008 AMC 8 Problems/Problem 5"

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==Solution==
 
==Solution==
Barney travels <math>1661-1441=220</math> miles in <math>5+6=11</math> hours for an average of <math>220/10=\boxed{\textbf{(E)}\ 22}</math> miles per hour.
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Barney travels <math>1661-1441=220</math> miles in <math>2+6=8</math> hours for an average of <math>220/10=\boxed{\textbf{(E)}\ 22}</math> miles per hour.
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2008|num-b=4|num-a=6}}
 
{{AMC8 box|year=2008|num-b=4|num-a=6}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 12:38, 27 March 2021

Problem

Barney Schwinn notices that the odometer on his bicycle reads $1441$, a palindrome, because it reads the same forward and backward. After riding $2$ more hours that day and $6$ the next, he notices that the odometer shows another palindrome, $1661$. What was his average speed in miles per hour?

$\textbf{(A)}\ 15\qquad \textbf{(B)}\ 16\qquad \textbf{(C)}\ 18\qquad \textbf{(D)}\ 20\qquad \textbf{(E)}\ 22$

Solution

Barney travels $1661-1441=220$ miles in $2+6=8$ hours for an average of $220/10=\boxed{\textbf{(E)}\ 22}$ miles per hour.

See Also

2008 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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