Difference between revisions of "2008 AMC 8 Problems/Problem 7"

Revision as of 01:30, 5 July 2013

Problem

If $\frac{3}{5}=\frac{M}{45}=\frac{60}{N}$ , what is $M+N$ ?

$\textbf{(A)}\ 27\qquad \textbf{(B)}\ 29 \qquad \textbf{(C)}\ 45 \qquad \textbf{(D)}\ 105\qquad \textbf{(E)}\ 127$

Solution

Separate into two equations $\frac35 = \frac{M}{45}$ and $\frac35 = \frac{60}{N}$ and solve for the unknowns. $M=27$ and $N=100$ , therefore $M+N=\boxed{\textbf{(E)}\ 127}$ .

2008 AMC 8 (Problems • Answer Key • Resources)
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All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions.

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 ==See Also==
 {{AMC8 box|year=2008|num-b=6|num-a=8}}
+{{MAA Notice}}

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Difference between revisions of "2008 AMC 8 Problems/Problem 7"

Revision as of 01:30, 5 July 2013

Problem

Solution

See Also