2008 AMC 8 Problems/Problem 7

Revision as of 17:00, 8 August 2021 by Raina0708 (talk | contribs) (Solution)

Problem

If $\frac{3}{5}=\frac{M}{45}=\frac{60}{N}$, what is $M+N$?

$\textbf{(A)}\ 27\qquad \textbf{(B)}\ 29 \qquad \textbf{(C)}\ 45 \qquad \textbf{(D)}\ 105\qquad \textbf{(E)}\ 127$

Solution

Separate into two equations 3 over 5 = m over 45 and 3 over 5 = 60 over N and solve for the unknowns. M=27 and N=100 so M+N=E 127 :D

See Also

2008 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png