Difference between revisions of "2008 AMC 8 Problems/Problem 8"

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</asy>
 
</asy>
 
<math> \textbf{(A)}\ 60\qquad\textbf{(B)}\ 70\qquad\textbf{(C)}\ 75\qquad\textbf{(D)}\ 80\qquad\textbf{(E)}\ 85 </math>
 
<math> \textbf{(A)}\ 60\qquad\textbf{(B)}\ 70\qquad\textbf{(C)}\ 75\qquad\textbf{(D)}\ 80\qquad\textbf{(E)}\ 85 </math>
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==Solution==
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There are a total of <math>100+60+40+120=320</math> dollars of sales spread through <math>4</math> months, for an average of <math>320/4 = \boxed{\textbf{(D)}\ 80}</math>.
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2008|num-b=7|num-a=9}}
 
{{AMC8 box|year=2008|num-b=7|num-a=9}}
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{{MAA Notice}}

Revision as of 01:30, 5 July 2013

Problem

Candy sales from the Boosters Club from January through April are shown. What were the average sales per month in dollars? [asy] draw((0,0)--(36,0)--(36,24)--(0,24)--cycle); draw((0,4)--(36,4)); draw((0,8)--(36,8)); draw((0,12)--(36,12)); draw((0,16)--(36,16)); draw((0,20)--(36,20)); fill((4,0)--(8,0)--(8,20)--(4,20)--cycle, black); fill((12,0)--(16,0)--(16,12)--(12,12)--cycle, black); fill((20,0)--(24,0)--(24,8)--(20,8)--cycle, black); fill((28,0)--(32,0)--(32,24)--(28,24)--cycle, black); label("$120", (0,24), W); label("$80", (0,16), W); label("$40", (0,8), W); label("Jan", (6,0), S); label("Feb", (14,0), S); label("Mar", (22,0), S); label("Apr", (30,0), S); [/asy] $\textbf{(A)}\ 60\qquad\textbf{(B)}\ 70\qquad\textbf{(C)}\ 75\qquad\textbf{(D)}\ 80\qquad\textbf{(E)}\ 85$

Solution

There are a total of $100+60+40+120=320$ dollars of sales spread through $4$ months, for an average of $320/4 = \boxed{\textbf{(D)}\ 80}$.

See Also

2008 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 7
Followed by
Problem 9
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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