Difference between revisions of "2008 UNCO Math Contest II Problems/Problem 5"

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== Solution ==  
 
== Solution ==  
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(a) <math>3^{668}\cdot 2^2</math> (b) <math>3^k</math> if <math>n=3k</math>;  <math>2^2\cdot 3^{k-1}</math> if <math>n=3k+1</math>;  <math>2\cdot 3^{k}</math> if <math>n=3k+2</math>
  
 
== See Also ==
 
== See Also ==

Latest revision as of 02:02, 13 January 2019

Problem

5. The sum of $400, 3, 500, 800$ and $305$ is $2008$ and the product of these five numbers is $146400000000 = 1464 \times 10^8.$

(a) Determine the largest number which is the product of positive integers whose sum is $2008$.

(b) Determine the largest number which is the product of positive integers whose sum is $n$.


Solution

(a) $3^{668}\cdot 2^2$ (b) $3^k$ if $n=3k$; $2^2\cdot 3^{k-1}$ if $n=3k+1$; $2\cdot 3^{k}$ if $n=3k+2$

See Also

2008 UNCO Math Contest II (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10
All UNCO Math Contest Problems and Solutions