2009 AIME I Problems/Problem 9

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Problem

A game show offers a contestant three prizes A, B and C, each of which is worth a whole number of dollars from <dollar/>$1$ to <dollar/>$9999$ inclusive. The contestant wins the prizes by correctly guessing the price of each prize in the order A, B, C. As a hint, the digits of the three prices are given. On a particular day, the digits given were $1, 1, 1, 1, 3, 3, 3$. Find the total number of possible guesses for all three prizes consistent with the hint.

Solution

Since we have 3 numbers, consider how many ways we can put this 3 number in a string of 7 digits by putting A,B,C together

For example: $A=113, B=13, C=31$

Then the string is

\[1131331\]

Since the strings have 7 digits and 3 three's. There are

$_7C_3$ of such string

In other to obtain all combination of A,B,C. We partition all the possible strings into 3 groups

Let look at the example.

We have to partition it into 3 groups with each group having at least 1 digit

We have to find solution where

\[x+y+z=7, 0<x,y,z<5\]

This gives us:

\[_6C_2\] (balls and urns)

But we have counted the one with 5 digit numbers. That is $(5,1,1),(1,1,5),(1,5,1)$

Thus, each arrangement has \[(_6C_2)-3=12\] ways per arrangement

Thus, there are $12\times35=\boxed{420}$ ways.

See also

2009 AIME I (ProblemsAnswer KeyResources)
Preceded by
Problem 8
Followed by
Problem 10
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All AIME Problems and Solutions