Difference between revisions of "2009 AMC 10A Problems/Problem 1"
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<math>10</math> cans would hold <math>120</math> ounces, but <math>128>120</math>, so <math>11</math> cans are required. Thus, the answer is <math>\mathrm{(E)}</math>. | <math>10</math> cans would hold <math>120</math> ounces, but <math>128>120</math>, so <math>11</math> cans are required. Thus, the answer is <math>\mathrm{(E)}</math>. | ||
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Revision as of 14:47, 15 February 2009
Problem
One can holds ounces of soda. What is the minimum number of cans needed to provide a gallon ( ounces) of soda?
Solution
cans would hold ounces, but , so cans are required. Thus, the answer is .
2009 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by First Question |
Followed by Problem 2 | |
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All AMC 10 Problems and Solutions |