Difference between revisions of "2009 AMC 10A Problems/Problem 1"
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We want to find <math>\left\lceil\frac{128}{12}\right\rceil</math> because there are a whole number of cans. | We want to find <math>\left\lceil\frac{128}{12}\right\rceil</math> because there are a whole number of cans. | ||
− | <math>\frac{128}{12} = 10R8\longrightarrow 11\longrightarrow \fbox{E}.</math> | + | <math>\frac{128}{12} = 10R8\longrightarrow 11\longrightarrow \fbox{(E)}.</math> |
{{AMC10 box|year=2009|ab=A|before=First Question|num-a=2}} | {{AMC10 box|year=2009|ab=A|before=First Question|num-a=2}} | ||
{{MAA Notice}} | {{MAA Notice}} |
Revision as of 12:44, 19 August 2018
Problem
One can, can hold ounces of soda, what is the minimum number of cans needed to provide a gallon ( ounces) of soda?
Solution 1
cans would hold ounces, but , so cans are required. Thus, the answer is .
Solution 2
We want to find because there are a whole number of cans.
2009 AMC 10A (Problems • Answer Key • Resources) | ||
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