2009 AMC 10A Problems/Problem 8

Revision as of 22:52, 12 February 2009 by Modx07 (talk | contribs) (New page: A senior ticket costs <dollar/><math>6.00</math>, so a regular ticket costs <math>6 * \frac{1}{\frac{3}{4}}\:=\:6*\frac{4}{3}\:=\:8</math> dollars. Therefore children's tickets cost half t...)
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A senior ticket costs <dollar/>$6.00$, so a regular ticket costs $6 * \frac{1}{\frac{3}{4}}\:=\:6*\frac{4}{3}\:=\:8$ dollars. Therefore children's tickets cost half that, or <dollar/>$4.00$, so we have:

$2(6+8+4)\:=\:36$

So Grandfather Wen pays <dollar/>$36$, or $B$.

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