Difference between revisions of "2009 AMC 10B Problems/Problem 1"
MRENTHUSIASM (talk | contribs) (This page is destroyed by the former contributors due to the false information. I am cleaning it up by inputting solutions. The correct wording can be found here: https://ivyleaguecenter.files.wordpress.com/2016/03/2009-amc-10b.pdf) |
MRENTHUSIASM (talk | contribs) |
||
| Line 2: | Line 2: | ||
== Problem == | == Problem == | ||
| − | Each morning of her five-day workweek, Jane bought either a 50-cent muffin or a 75-cent bagel. | + | Each morning of her five-day workweek, Jane bought either a 50-cent muffin or a 75-cent bagel. Her total cost for the week was a whole number of dollars. How many bagels did she buy? |
<math>\text{(A) } 1\qquad\text{(B) } 2\qquad\text{(C) } 3\qquad\text{(D) } 4\qquad\text{(E) } 5</math> | <math>\text{(A) } 1\qquad\text{(B) } 2\qquad\text{(C) } 3\qquad\text{(D) } 4\qquad\text{(E) } 5</math> | ||
| + | |||
| + | == Solution 1 (Algebra) == | ||
| + | A muffin costed <math>2</math> quarters, and a bagel costed <math>3</math> quarters. | ||
| + | |||
| + | Suppose that Jane bought <math>m</math> muffins and <math>b</math> bagels, where <math>m</math> and <math>b</math> are nonnegative integers. We need: | ||
| + | <ol style="margin-left: 1.5em;"> | ||
| + | <li><math>m+b=5.</math></li><p> | ||
| + | <li><math>2m+3b</math> is divisible by <math>4.</math></li><p> | ||
| + | </ol> | ||
| + | From the second condition, it is clear that <math>b</math> must be even. By a quick inspection, the only solution is <math>(m,b)=(3,2),</math> so the answer is <math>b=\boxed{\text{(B) } 2}.</math> | ||
| + | |||
| + | ~MRENTHUSIASM | ||
== See also == | == See also == | ||
Revision as of 16:31, 9 June 2021
- The following problem is from both the 2009 AMC 10B #1 and 2009 AMC 12B #1, so both problems redirect to this page.
Problem
Each morning of her five-day workweek, Jane bought either a 50-cent muffin or a 75-cent bagel. Her total cost for the week was a whole number of dollars. How many bagels did she buy?
Solution 1 (Algebra)
A muffin costed 
quarters, and a bagel costed 
quarters.
Suppose that Jane bought 
muffins and 
bagels, where and are nonnegative integers. We need:
is divisible by 
is divisible by 
From the second condition, it is clear that must be even. By a quick inspection, the only solution is 
so the answer is 
~MRENTHUSIASM
See also
| 2009 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
| 2009 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by First Question |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
