Difference between revisions of "2009 AMC 10B Problems/Problem 1"
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The only combination of five items with total cost a whole number of dollars is 3 muffins and <math>\boxed {2}</math> bagels. The answer is <math>\mathrm{(B)}</math>. | The only combination of five items with total cost a whole number of dollars is 3 muffins and <math>\boxed {2}</math> bagels. The answer is <math>\mathrm{(B)}</math>. | ||
| + | == See also == | ||
{{AMC10 box|year=2009|ab=B|before=First Question|num-a=2}} | {{AMC10 box|year=2009|ab=B|before=First Question|num-a=2}} | ||
{{AMC12 box|year=2009|ab=B|before=First Question|num-a=2}} | {{AMC12 box|year=2009|ab=B|before=First Question|num-a=2}} | ||
Revision as of 19:00, 26 February 2009
- The following problem is from both the 2009 AMC 10B #1 and 2009 AMC 12B #1, so both problems redirect to this page.
Problem
Each morning of her five-day workweek, Jane bought either a 50-cent muffin or a 75-cent bagel. Her total cost for the week was a whole number of dollars, How many bagels did she buy?
Solution
The only combination of five items with total cost a whole number of dollars is 3 muffins and 
bagels. The answer is 
.
See also
| 2009 AMC 10B (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
| 2009 AMC 12B (Problems • Answer Key • Resources) | |
| Preceded by First Question |
Followed by Problem 2 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
