Difference between revisions of "2010 AMC 10A Problems/Problem 6"
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<math>\spadesuit(2, 2) = 2 - \frac{1}{2} = \frac{3}{2}</math>. Then, <math>\spadesuit(2, \frac{3}{2})</math> is <math>2-\frac{1}{\frac{3}{2}} = 2- \frac{2}{3} = \frac{4}{3}</math> | <math>\spadesuit(2, 2) = 2 - \frac{1}{2} = \frac{3}{2}</math>. Then, <math>\spadesuit(2, \frac{3}{2})</math> is <math>2-\frac{1}{\frac{3}{2}} = 2- \frac{2}{3} = \frac{4}{3}</math> | ||
The answer is <math>\boxed{C}</math> | The answer is <math>\boxed{C}</math> | ||
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+ | == See Also == | ||
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+ | {{AMC10 box|year=2010|ab=A|num-b=5|num-a=7}} |
Revision as of 19:38, 1 January 2012
Problem 6
For positive numbers and the operation is defined as
What is ?
Solution
. Then, is The answer is
See Also
2010 AMC 10A (Problems • Answer Key • Resources) | ||
Preceded by Problem 5 |
Followed by Problem 7 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
All AMC 10 Problems and Solutions |