Difference between revisions of "2010 AMC 10B Problems/Problem 10"

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==Problem==
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#redirect [[2010 AMC 12B Problems/Problem 7]]
Shelby drives her scooter at a speed of <math>30</math> miles per hour if it is not raining, and <math>20</math> miles per hour if it is raining. Today she drove in the sun in the morning and in the rain in the evening, for a total of <math>16</math> miles in <math>40</math> minutes. How many minutes did she drive in the rain?
 
 
 
<math>\textbf{(A)}\ 18 \qquad \textbf{(B)}\ 21 \qquad \textbf{(C)}\ 24 \qquad \textbf{(D)}\ 27 \qquad \textbf{(E)}\ 30</math>
 
 
 
==Solution 1==
 
We know that <math>d = rt</math>
 
 
 
Since we know that she drove both when it was raining and when it was not and that her total distance traveled is <math>16</math> miles.
 
 
 
We also know that she drove a total of <math>40</math> minutes which is <math>\dfrac{2}{3}</math> of an hour.
 
 
 
We get the following system of equations, where <math>x</math> is the time traveled when it was not raining and <math>y</math> is the time traveled when it was raining:
 
 
 
<math>\left\{\begin{array}{ccc} 30x + 20y & = & 16 \\x + y & = & \dfrac{2}{3} \end{array} \right.</math>
 
 
 
Solving the above equations by multiplying the second equation by 30 and subtracting the second equation from the first we get:
 
 
 
<math>-10y = -4 \Leftrightarrow y = \dfrac{2}{5}</math>
 
 
 
We know now that the time traveled in rain was <math>\dfrac{2}{5}</math> of an hour, which is <math>\dfrac{2}{5}*60 = 24</math> minutes
 
 
 
So, our answer is <math> \boxed{\textbf{(C)}\ 24} </math>
 
 
 
==Solution 2==
 
We let <math>t</math> be the time Shelby drives in the rain. This gives us the equation <math> 20t + 30\left(\frac{2}{3} - t \right ) = 16</math>. Expanding and rearranging gives us <math>10t = 4</math>, or <math>t = 0.4</math> hours. we multiply <math>0.4</math> by <math>60</math>, which gives us <math> \boxed{\textbf{(C)}\ 24} </math>.
 
 
 
== Solution 3==
 
Shelby's overall speed is <math>\frac{16}{40} \cdot 60 = 24</math> miles per hour. Since <math>24</math> is <math>\frac23</math> as close to <math>20</math> as it is from <math>30</math>, Shelby spent <math>\frac32</math> as much time in the rain as she did in the sun, or <math>\frac{3}{2+3}=\frac35</math> of the total time. <math>\frac35 \cdot 40 = \boxed{\textbf{(C)}\ 24}</math>
 
 
 
==See Also==
 
{{AMC10 box|year=2010|ab=B|num-b=9|num-a=11}}
 
{{MAA Notice}}
 

Latest revision as of 20:39, 26 May 2020