Difference between revisions of "2010 AMC 10B Problems/Problem 16"

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Area of Circle = <math>&pi r^2 = &pi/3</math>
+
Area of Circle = <math>\pi r^2 = \frac{\pi}{3}</math>
  
 
Area of Square = <math>1^2 = 1</math>
 
Area of Square = <math>1^2 = 1</math>
  
Therefore answer = (A) <math>&pi/3 - 1</math>
+
Therefore answer = (A) <math>\frac{\pi}{3} - 1</math>

Revision as of 01:49, 1 March 2011

Area of Circle = $\pi r^2 = \frac{\pi}{3}$

Area of Square = $1^2 = 1$

Therefore answer = (A) $\frac{\pi}{3} - 1$

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