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2010 AMC 10B Problems/Problem 16

Revision as of 02:49, 1 March 2011 by Sanchitb (talk | contribs)

Area of Circle = $\pi r^2 = \frac{\pi}{3}$

Area of Square = $1^2 = 1$

Therefore answer = (A) $\frac{\pi}{3} - 1$

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