Difference between revisions of "2010 AMC 12B Problems/Problem 1"

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{{duplicate|[[2010 AMC 12B Problems|2010 AMC 12B #1]] and [[2010 AMC 10B Problems|2010 AMC 10B #2]]}}
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== Problem ==
 
== Problem ==
 
Makarla attended two meetings during her <math>9</math>-hour work day. The first meeting took <math>45</math> minutes and the second meeting took twice as long. What percent of her work day was spent attending meetings?
 
Makarla attended two meetings during her <math>9</math>-hour work day. The first meeting took <math>45</math> minutes and the second meeting took twice as long. What percent of her work day was spent attending meetings?
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== Solution ==
 
== Solution ==
The total number of minutes in here <math>9</math>-hour work day is <math>9 \times 60 = 540.</math>
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The total number of minutes in her <math>9</math>-hour work day is <math>9 \times 60 = 540.</math>
 
The total amount of time spend in meetings in minutes is <math>45 + 45 \times 2 = 135.</math>
 
The total amount of time spend in meetings in minutes is <math>45 + 45 \times 2 = 135.</math>
The answer is then <math>\frac{135}{540}</math> <math>= \boxed{25\%}</math> <math>\LongRightArrow</math> <math>(C)</math>
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The answer is then <math>\frac{135}{540}</math> <math>= \boxed{25\%}</math> or  <math>\boxed{(C)}</math>
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==Video Solution==
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https://youtu.be/8yntxcttyd8
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-Education, the Study of Everything
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==Video Solution==
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https://youtu.be/uAc9VHtRRPg?t=82
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~IceMatrix
  
 
== See also ==
 
== See also ==
{{AMC12 box|year=2010|num-b=1|num-a=2|ab=B}}
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{{AMC12 box|year=2010|before=First Question|num-a=2|ab=B}}
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{{AMC10 box|year=2010|ab=B|num-b=1|num-a=3}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Latest revision as of 15:59, 1 August 2022

The following problem is from both the 2010 AMC 12B #1 and 2010 AMC 10B #2, so both problems redirect to this page.

Problem

Makarla attended two meetings during her $9$-hour work day. The first meeting took $45$ minutes and the second meeting took twice as long. What percent of her work day was spent attending meetings?

$\textbf{(A)}\ 15 \qquad \textbf{(B)}\ 20 \qquad \textbf{(C)}\ 25 \qquad \textbf{(D)}\ 30 \qquad \textbf{(E)}\ 35$

Solution

The total number of minutes in her $9$-hour work day is $9 \times 60 = 540.$ The total amount of time spend in meetings in minutes is $45 + 45 \times 2 = 135.$ The answer is then $\frac{135}{540}$ $= \boxed{25\%}$ or $\boxed{(C)}$

Video Solution

https://youtu.be/8yntxcttyd8

-Education, the Study of Everything

Video Solution

https://youtu.be/uAc9VHtRRPg?t=82

~IceMatrix

See also

2010 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
First Question
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions
2010 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png

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