Difference between revisions of "2010 AMC 12B Problems/Problem 4"

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== Solution ==
 
== Solution ==
 
<math>31 \equiv 3 \pmod {7}</math> so the week cannot start with Saturday, Sunday, Tuesday or Wednesday as that would result in an unequal number of Mondays and Wednesdays. Therefore, Monday, Thursday, and Friday are valid so the answer is <math>\boxed{B}</math>.
 
<math>31 \equiv 3 \pmod {7}</math> so the week cannot start with Saturday, Sunday, Tuesday or Wednesday as that would result in an unequal number of Mondays and Wednesdays. Therefore, Monday, Thursday, and Friday are valid so the answer is <math>\boxed{B}</math>.
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==Video Solution==
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https://youtu.be/uAc9VHtRRPg?t=329
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~IceMatrix
  
 
== See also ==
 
== See also ==
 
{{AMC12 box|year=2010|num-b=3|num-a=5|ab=B}}
 
{{AMC12 box|year=2010|num-b=3|num-a=5|ab=B}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 02:57, 26 September 2020

The following problem is from both the 2010 AMC 12B #4 and 2010 AMC 10B #5, so both problems redirect to this page.

Problem 4

A month with $31$ days has the same number of Mondays and Wednesdays.How many of the seven days of the week could be the first day of this month?

$\textbf{(A)}\ 2 \qquad \textbf{(B)}\ 3 \qquad \textbf{(C)}\ 4 \qquad \textbf{(D)}\ 5 \qquad \textbf{(E)}\ 6$

Solution

$31 \equiv 3 \pmod {7}$ so the week cannot start with Saturday, Sunday, Tuesday or Wednesday as that would result in an unequal number of Mondays and Wednesdays. Therefore, Monday, Thursday, and Friday are valid so the answer is $\boxed{B}$.

Video Solution

https://youtu.be/uAc9VHtRRPg?t=329

~IceMatrix

See also

2010 AMC 12B (ProblemsAnswer KeyResources)
Preceded by
Problem 3
Followed by
Problem 5
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions

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