Difference between revisions of "2010 AMC 8 Problems/Problem 14"

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<math> \textbf{(A)}\ 67\qquad\textbf{(B)}\ 75\qquad\textbf{(C)}\ 77\qquad\textbf{(D)}\ 201\qquad\textbf{(E)}\ 210 </math>
 
<math> \textbf{(A)}\ 67\qquad\textbf{(B)}\ 75\qquad\textbf{(C)}\ 77\qquad\textbf{(D)}\ 201\qquad\textbf{(E)}\ 210 </math>
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==Video Solution==
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https://youtu.be/6xNkyDgIhEE?t=1236
  
 
==Solution==
 
==Solution==

Revision as of 22:31, 12 August 2020

Problem

What is the sum of the prime factors of $2010$?

$\textbf{(A)}\ 67\qquad\textbf{(B)}\ 75\qquad\textbf{(C)}\ 77\qquad\textbf{(D)}\ 201\qquad\textbf{(E)}\ 210$

Video Solution

https://youtu.be/6xNkyDgIhEE?t=1236

Solution

First, we must find the prime factorization of $2010$. $2010=2\cdot 3 \cdot 5 \cdot 67$. We add the factors up to get $\boxed{\textbf{(C)}\ 77}$

See Also

2010 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 13
Followed by
Problem 15
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All AJHSME/AMC 8 Problems and Solutions

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