2010 AMC 8 Problems/Problem 7

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Solution

You need $2$ dimes, $1$ nickel, and $4$ pennies for the first $25$ cents. From $26$ cents to $50$ cents, you only need to add $1$ quarter. From $51$ cents to $75$ cents, you also only need to add $1$ quarter. The same for $76$ cents to $99$ cents. Notice that we didn't put $100$ instead of $99$. We are left with $3$ quarters, $2$ dimes, $1$ nickel, and $4$ pennies. Thus, the correct answer is $3+2+1+4=\boxed{\text{(B) } 10}$.

See Also

2010 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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