Difference between revisions of "2011 AMC 10A Problems/Problem 1"
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<math> \textbf{(A)}\ </math> <math>24.00 \qquad\textbf{(B)}\ </math> <math>24.50 \qquad\textbf{(C)}\ </math> <math>25.50\qquad\textbf{(D)}\ </math> <math>28.00\qquad\textbf{(E)}\ </math> <math>30.00 </math> | <math> \textbf{(A)}\ </math> <math>24.00 \qquad\textbf{(B)}\ </math> <math>24.50 \qquad\textbf{(C)}\ </math> <math>25.50\qquad\textbf{(D)}\ </math> <math>28.00\qquad\textbf{(E)}\ </math> <math>30.00 </math> | ||
| − | == Solution == | + | <math></math>== Solution == |
<math>30.5-30 = .5</math> hours which is <math>30</math> minutes. <math>30*10=300</math> cents which is <math>3</math> dollars. <math>100*.05=5</math> dollars. So finally <math>20+3+5=28</math> dollars. <math>\longrightarrow \boxed{\textbf{D}}</math> | <math>30.5-30 = .5</math> hours which is <math>30</math> minutes. <math>30*10=300</math> cents which is <math>3</math> dollars. <math>100*.05=5</math> dollars. So finally <math>20+3+5=28</math> dollars. <math>\longrightarrow \boxed{\textbf{D}}</math> | ||
== See Also == | == See Also == | ||
{{AMC10 box|year=2011|ab=A|before=First Question|num-a=2}} | {{AMC10 box|year=2011|ab=A|before=First Question|num-a=2}} | ||
Revision as of 18:44, 3 February 2013
Problem 1
A cell phone plan costs 
each month, plus 
¢ per text message sent, plus 
¢ for each minute used over 
hours. In January Michelle sent 
text messages and talked for 
hours. How much did she have to pay?
$$ (Error compiling LaTeX. Unknown error_msg)== Solution ==
hours which is minutes. 
cents which is 
dollars. 
dollars. So finally 
dollars. 
See Also
| 2011 AMC 10A (Problems • Answer Key • Resources) | ||
| Preceded by First Question |
Followed by Problem 2 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AMC 10 Problems and Solutions | ||
