Difference between revisions of "2011 AMC 10A Problems/Problem 1"

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== Problem 1 ==
 
== Problem 1 ==
A cell phone plan costs <cmath>0.36</cmath>20<math> each month, plus </math>5<math>¢ per text message sent, plus </math>10<math>¢ for each minute used over </math>30<math> hours. In January Michelle sent </math>100<math> text messages and talked for </math>30.5<math> hours. How much did she have to pay?
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A cell phone plan costs <math>\mathdollar 20</math> each month, plus <math>5</math>¢ per text message sent, plus <math>10</math>¢ for each minute used over <math>30</math> hours. In January Michelle sent <math>100</math> text messages and talked for <math>30.5</math> hours. How much did she have to pay?
  
</math> \textbf{(A)}\ <math> </math>24.00 \qquad\textbf{(B)}\ <math> </math>24.50 \qquad\textbf{(C)}\ <math> </math>25.50\qquad\textbf{(D)}\ <math> </math>28.00\qquad\textbf{(E)}\ <math> </math>30.00 <math>
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<math> \textbf{(A)}\;\mathdollar 24.00 \qquad\textbf{(B)}\;\mathdollar 24.50 \qquad\textbf{(C)}\;\mathdollar 25.50\qquad\textbf{(D)}\;\mathdollar 28.00\qquad\textbf{(E)}\;\mathdollar 30.00 </math>
  
 
== Solution ==
 
== Solution ==
</math>30.5-30 = .5<math> hours which is </math>30<math> minutes. </math>30*10=300<math> cents which is </math>3<math> dollars. </math>100*.05=5<math> dollars. So finally </math>20+3+5=28<math> dollars. </math>\longrightarrow \boxed{\textbf{D}}$
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<math>30.5-30 = .5</math> hours which is <math>30</math> minutes. <math>30*10=300</math> cents which is <math>3</math> dollars. <math>100*.05=5</math> dollars. So finally <math>20+3+5=28</math> dollars. <math>\longrightarrow \boxed{\textbf{D}}</math>
  
 
== See Also ==
 
== See Also ==
 
{{AMC10 box|year=2011|ab=A|before=First Question|num-a=2}}
 
{{AMC10 box|year=2011|ab=A|before=First Question|num-a=2}}

Revision as of 15:41, 18 June 2013

Problem 1

A cell phone plan costs $\mathdollar 20$ each month, plus $5$¢ per text message sent, plus $10$¢ for each minute used over $30$ hours. In January Michelle sent $100$ text messages and talked for $30.5$ hours. How much did she have to pay?

$\textbf{(A)}\;\mathdollar 24.00 \qquad\textbf{(B)}\;\mathdollar 24.50 \qquad\textbf{(C)}\;\mathdollar 25.50\qquad\textbf{(D)}\;\mathdollar 28.00\qquad\textbf{(E)}\;\mathdollar 30.00$

Solution

$30.5-30 = .5$ hours which is $30$ minutes. $30*10=300$ cents which is $3$ dollars. $100*.05=5$ dollars. So finally $20+3+5=28$ dollars. $\longrightarrow \boxed{\textbf{D}}$

See Also

2011 AMC 10A (ProblemsAnswer KeyResources)
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First Question
Followed by
Problem 2
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All AMC 10 Problems and Solutions