Difference between revisions of "2011 AMC 12A Problems/Problem 17"
(→Problem) |
(→Solution) |
||
| Line 10: | Line 10: | ||
== Solution == | == Solution == | ||
| + | |||
| + | |||
| + | |||
| + | |||
| + | Area of the triangle | ||
| + | |||
| + | <math> = \frac{1}{2} \times 4 \times 3 - \frac{1}{2} \times 1 \times 1 - \frac{1}{2} \times 3 \times 3 \times \frac{3}{5} - \frac{1}{2} \times 2 \times 2 \times \frac{4}{5} </math> | ||
| + | |||
| + | <math> = \frac{6}{5} </math> | ||
| + | |||
== See also == | == See also == | ||
{{AMC12 box|year=2011|num-b=16|num-a=18|ab=A}} | {{AMC12 box|year=2011|num-b=16|num-a=18|ab=A}} | ||
Revision as of 03:29, 11 February 2011
Problem
Circles with radii 
, 
, and 
are mutually externally tangent. What is the area of the triangle determine by the points of tangency?
Solution
Area of the triangle
See also
| 2011 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 16 |
Followed by Problem 18 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
