Difference between revisions of "2011 AMC 12A Problems/Problem 3"

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== Problem ==
 
== Problem ==
 
== Solution ==
 
== Solution ==
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To find how many small bottles we need, we can simply divide 500 by 35. This simplifies to 100/7=14+2/7. Since the answer must be an integer greater than 14, we have to round up to 15 bottles='''(E)'''
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== See also ==
 
== See also ==
 
{{AMC12 box|year=2011|num-b=2|num-a=4|ab=A}}
 
{{AMC12 box|year=2011|num-b=2|num-a=4|ab=A}}

Revision as of 20:09, 9 February 2011

Problem

Solution

To find how many small bottles we need, we can simply divide 500 by 35. This simplifies to 100/7=14+2/7. Since the answer must be an integer greater than 14, we have to round up to 15 bottles=(E)

See also

2011 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions
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