Difference between revisions of "2011 AMC 12A Problems/Problem 5"
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== Solution == | == Solution == | ||
| − | To simplify the problem, let us say that there were a total of 100 birds. The number of birds that are not swans is 75. The number of geese is 30. Therefore the percentage is just <math>\frac{30}{75} \times 100 = 40 \Rightarrow \boxed{C}</math> | + | To simplify the problem, let us say that there were a total of <math>100</math> birds. The number of birds that are not swans is <math>75</math>. The number of geese is <math>30</math>. Therefore the percentage is just <math>\frac{30}{75} \times 100 = 40 \Rightarrow \boxed{C}</math> |
== See also == | == See also == | ||
{{AMC12 box|year=2011|num-b=4|num-a=6|ab=A}} | {{AMC12 box|year=2011|num-b=4|num-a=6|ab=A}} | ||
Revision as of 20:05, 10 February 2011
Problem
Last summer $30%$ (Error compiling LaTeX. Unknown error_msg) of the birds living on Town Lake were geese, $25%$ (Error compiling LaTeX. Unknown error_msg) were swans, $10%$ (Error compiling LaTeX. Unknown error_msg) were herons, and $35%$ (Error compiling LaTeX. Unknown error_msg) were ducks. What percent of the birds that were not swans were geese?
Solution
To simplify the problem, let us say that there were a total of 
birds. The number of birds that are not swans is 
. The number of geese is 
. Therefore the percentage is just 
See also
| 2011 AMC 12A (Problems • Answer Key • Resources) | |
| Preceded by Problem 4 |
Followed by Problem 6 |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
| All AMC 12 Problems and Solutions | |
