Difference between revisions of "2011 AMC 12A Problems/Problem 6"
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Set that equal to <math>61</math>, we get <math>x = 4</math>, and therefore the number of free throws they made <math>3 \times 4 + 1 = 13 \Rightarrow \boxed{A}</math> | Set that equal to <math>61</math>, we get <math>x = 4</math>, and therefore the number of free throws they made <math>3 \times 4 + 1 = 13 \Rightarrow \boxed{A}</math> | ||
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== Solution 2 == | == Solution 2 == |
Revision as of 00:24, 30 October 2018
Contents
Problem
The players on a basketball team made some three-point shots, some two-point shots, and some one-point free throws. They scored as many points with two-point shots as with three-point shots. Their number of successful free throws was one more than their number of successful two-point shots. The team's total score was points. How many free throws did they make?
Solution 1
For the points made from two-point shots and from three-point shots to be equal, the numbers of made shots are in a ratio. Therefore, assume they made and two- and three- point shots, respectively, and thus free throws. The total number of points is
Set that equal to , we get , and therefore the number of free throws they made
Solution 2
Let be the number of free throws. Then the number of points scored by two-pointers is and the same goes for three-pointers because they scored the same number of points with twos and threes. Thus, our equation is , giving us for an answer.
See also
2011 AMC 12A (Problems • Answer Key • Resources) | |
Preceded by Problem 5 |
Followed by Problem 7 |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | |
All AMC 12 Problems and Solutions |
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