Difference between revisions of "2011 AMC 12A Problems/Problem 7"

(Problem)
(Problem)
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== Problem ==
 
== Problem ==
A majority of the 30 students in Ms. Demeanor's class bought pencils at the school bookstore. Each of these students bought the same number of pencils, and this number was greater than 1. The cost of a pencil in cents was greater than the number of pencils each student bought, and the total cost of all the pencils was <math>\</math>17.71. What was the cost of a pencil in cents?
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A majority of the <math>30</math> students in Ms. Demeanor's class bought pencils at the school bookstore. Each of these students bought the same number of pencils, and this number was greater than <math>1</math>. The cost of a pencil in cents was greater than the number of pencils each student bought, and the total cost of all the pencils was <math>17.71</math>. What was the cost of a pencil in cents?
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<math> \textbf{(A)}\ 7 \qquad
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<math>
 +
\textbf{(A)}\ 7 \qquad
 
\textbf{(B)}\ 11 \qquad
 
\textbf{(B)}\ 11 \qquad
 
\textbf{(C)}\ 17 \qquad
 
\textbf{(C)}\ 17 \qquad
\textbf{(D)}\ 23 \qquad
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\textbf{(D)}\ 23 \qquad
\textbf{(E)}\ 77
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\textbf{(E)}\ 77 </math>
</math>
 
  
 
== Solution ==
 
== Solution ==
 
== See also ==
 
== See also ==
 
{{AMC12 box|year=2011|num-b=6|num-a=8|ab=A}}
 
{{AMC12 box|year=2011|num-b=6|num-a=8|ab=A}}

Revision as of 02:32, 10 February 2011

Problem

A majority of the $30$ students in Ms. Demeanor's class bought pencils at the school bookstore. Each of these students bought the same number of pencils, and this number was greater than $1$. The cost of a pencil in cents was greater than the number of pencils each student bought, and the total cost of all the pencils was $17.71$. What was the cost of a pencil in cents?

$\textbf{(A)}\ 7 \qquad \textbf{(B)}\ 11 \qquad \textbf{(C)}\ 17 \qquad \textbf{(D)}\ 23 \qquad \textbf{(E)}\ 77$

Solution

See also

2011 AMC 12A (ProblemsAnswer KeyResources)
Preceded by
Problem 6
Followed by
Problem 8
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 12 Problems and Solutions