2011 AMC 12B Problems/Problem 9
Revision as of 20:14, 10 March 2011 by Applepi2000 (talk | contribs) (Created page with 'For the product to be greater than zero, we must have either both numbers negative or both positive. Both numbers are negative with a <math>\frac{2}{3}*\frac{2}{3}=\frac{4}{9}<…')
For the product to be greater than zero, we must have either both numbers negative or both positive.
Both numbers are negative with a 
chance.
Both numbers are positive with a 
chance.
Therefore, the total probability is 
and we are done. 
