Difference between revisions of "2011 AMC 8 Problems/Problem 1"

m (Problem: Spelling error)
(Solution)
Line 6: Line 6:
 
==Solution==
 
==Solution==
  
<math>50</math> cents is equivalent to <math>\textdollar 0.50.</math> Then the three apples cost <math>3 \times \textdollar 0.50 = \textdollar 1.50.</math> The change Margie receives is <math>\textdollar 5.00 - \textdollar 1.50 = \boxed{\textbf{(E)}\ \textdollar 3.50}</math>
+
<math>50</math> cents is equivalent to <math>\textdollar 0.50.</math> Then the three apples cost <math>3 \times \textdollar 0.50 = \textdollar 1.50.</math> The change Idiot receives is <math>\textdollar 5.00 - \textdollar 1.50 = \boxed{\textbf{(E)}\ \textdollar 3.50}</math>
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2011|before=First Problem|num-a=2}}
 
{{AMC8 box|year=2011|before=First Problem|num-a=2}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 20:03, 27 December 2021

Problem

Margie bought $3$ apples at a cost of $50$ cents per apple. She paid with a 5-dollar bill. How much change did Margie receive?

$\textbf{(A)}\ \textdollar 1.50 \qquad \textbf{(B)}\ \textdollar 2.00 \qquad \textbf{(C)}\ \textdollar 2.50 \qquad \textbf{(D)}\ \textdollar 3.00 \qquad \textbf{(E)}\ \textdollar 3.50$

Solution

$50$ cents is equivalent to $\textdollar 0.50.$ Then the three apples cost $3 \times \textdollar 0.50 = \textdollar 1.50.$ The change Idiot receives is $\textdollar 5.00 - \textdollar 1.50 = \boxed{\textbf{(E)}\ \textdollar 3.50}$

See Also

2011 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
First Problem
Followed by
Problem 2
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png