Difference between revisions of "2011 AMC 8 Problems/Problem 10"

(Solution)
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Let <math>x</math> be the number of miles you ride. The number of miles you ride after the first half mile is <math>x-0.5.</math> We can write this equation:
 
Let <math>x</math> be the number of miles you ride. The number of miles you ride after the first half mile is <math>x-0.5.</math> We can write this equation:
  
<cmath>\begin{align*} 10 &= 2.4 + 0.2 \times \frac{x-0.5}{0.1} + 2\\
+
<cmath>\begin{align} 10 &= 2.4 + 0.2 \times \frac{x-0.5}{0.1} + 2\\
 
5.6 &= 2(x-0.5)\\
 
5.6 &= 2(x-0.5)\\
 
2.8 &= x-0.5\\
 
2.8 &= x-0.5\\
x &= \boxed{\textbf{(C)}\ 3.3}\end{align*}</cmath>
+
x &= \boxed{\textbf{(C)}\ 3.3}\end{align}</cmath>
  
 
==See Also==
 
==See Also==
 
{{AMC8 box|year=2011|num-b=9|num-a=11}}
 
{{AMC8 box|year=2011|num-b=9|num-a=11}}
 
{{MAA Notice}}
 
{{MAA Notice}}

Revision as of 20:03, 17 August 2021

Problem

The taxi fare in Gotham City is $2.40 for the first $\frac12$ mile and additional mileage charged at the rate $0.20 for each additional 0.1 mile. You plan to give the driver a $2 tip. How many miles can you ride for $10?

$\textbf{(A) }3.0\qquad\textbf{(B) }3.25\qquad\textbf{(C) }3.3\qquad\textbf{(D) }3.5\qquad\textbf{(E) }3.75$

Solution

Let $x$ be the number of miles you ride. The number of miles you ride after the first half mile is $x-0.5.$ We can write this equation:

\begin{align} 10 &= 2.4 + 0.2 \times \frac{x-0.5}{0.1} + 2\\ 5.6 &= 2(x-0.5)\\ 2.8 &= x-0.5\\ x &= \boxed{\textbf{(C)}\ 3.3}\end{align}

See Also

2011 AMC 8 (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AJHSME/AMC 8 Problems and Solutions

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