Difference between revisions of "2011 AMC 8 Problems/Problem 4"
| (One intermediate revision by one other user not shown) | |||
| Line 1: | Line 1: | ||
| + | ==Problem== | ||
Here is a list of the numbers of fish that Tyler caught in nine outings last summer: <cmath>2,0,1,3,0,3,3,1,2.</cmath> Which statement about the mean, median, and mode is true? | Here is a list of the numbers of fish that Tyler caught in nine outings last summer: <cmath>2,0,1,3,0,3,3,1,2.</cmath> Which statement about the mean, median, and mode is true? | ||
| Line 13: | Line 14: | ||
==See Also== | ==See Also== | ||
{{AMC8 box|year=2011|num-b=3|num-a=5}} | {{AMC8 box|year=2011|num-b=3|num-a=5}} | ||
| + | {{MAA Notice}} | ||
Latest revision as of 01:58, 5 July 2013
Problem
Here is a list of the numbers of fish that Tyler caught in nine outings last summer: ![\[2,0,1,3,0,3,3,1,2.\]](http://latex.artofproblemsolving.com/6/b/7/6b7acd21d15b3e6744a3b750c1c6fbd688b75635.png)
Which statement about the mean, median, and mode is true?
Solution
First, put the numbers in increasing order.
![\[0,0,1,1,2,2,3,3,3\]](http://latex.artofproblemsolving.com/3/d/7/3d76e96d7a46a5eacd2956de74936b866cd03a45.png)
The mean is 
the median is 
and the mode is 
Because, 
the answer is 
See Also
| 2011 AMC 8 (Problems • Answer Key • Resources) | ||
| Preceded by Problem 3 |
Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| All AJHSME/AMC 8 Problems and Solutions | ||
The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. 
