Difference between revisions of "2012 AIME II Problems/Problem 10"

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Note: <math>\lfloor x \rfloor</math> is the greatest integer less than or equal to <math>x</math>.
 
Note: <math>\lfloor x \rfloor</math> is the greatest integer less than or equal to <math>x</math>.
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== Solution ==
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== See also ==
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{{AIME box|year=2012|n=II|num-b=9|num-a=11}}

Revision as of 17:21, 31 March 2012

Problem 10

Find the number of positive integers $n$ less than $1000$ for which there exists a positive real number $x$ such that $n=x\lfloor x \rfloor$.

Note: $\lfloor x \rfloor$ is the greatest integer less than or equal to $x$.


Solution

See also

2012 AIME II (ProblemsAnswer KeyResources)
Preceded by
Problem 9
Followed by
Problem 11
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All AIME Problems and Solutions
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