2012 AIME I Problems/Problem 10

Problem 10

Let $\mathcal{S}$ be the set of all perfect squares whose rightmost three digits in base $10$ are $256$ . Let $\mathcal{T}$ be the set of all numbers of the form $\frac{x-256}{1000}$ , where $x$ is in $\mathcal{S}$ . In other words, $\mathcal{T}$ is the set of numbers that result when the last three digits of each number in $\mathcal{S}$ are truncated. Find the remainder when the tenth smallest element of $\mathcal{T}$ is divided by $1000$ .

2012 AIME I (Problems • Answer Key • Resources)
Preceded by Problem 9	Followed by Problem 11
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2012 AIME I Problems/Problem 10

Problem 10

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