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Difference between revisions of "2012 AMC 10A Problems/Problem 3"

(Problem 3)
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== Solution ==
 
== Solution ==
  
Crawling from -2 to -6 takes it a distance of 4 units. Crawling from -6 to 5 takes it a distance of 11 units. Add the two to get <math>\qquad\textbf{(E)}\ 15</math>
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Crawling from -2 to -6 takes it a distance of 4 units. Crawling from -6 to 5 takes it a distance of 11 units. Add 4 and 11 to get <math>\qquad\textbf{(E)}\ 15</math>

Revision as of 19:17, 8 February 2012

Problem 3

A bug crawls along a number line, starting at -2. It crawls to -6, then turns around and crawls to 5. How many units does the bug crawl altogether?

$\textbf{(A)}\ 9\qquad\textbf{(B)}\ 11\qquad\textbf{(C)}\ 13\qquad\textbf{(D)}\ 14\qquad\textbf{(E)}\ 15$

Solution

Crawling from -2 to -6 takes it a distance of 4 units. Crawling from -6 to 5 takes it a distance of 11 units. Add 4 and 11 to get $\qquad\textbf{(E)}\ 15$

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