Difference between revisions of "2012 AMC 10B Problems/Problem 20"

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==Solution==
 
==Solution==
  
Let's test each solution, for our first case <math>7</math>, we start out with <math>7</math> and the number is then given to Bernardo. He will double the given number so in this case <math>7\times 2\=14</math>
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Let's test each solution, for our first case <math>7</math>, we start out with <math>7</math> and the number is then given to Bernardo. He will double the given number so in this case <math>7\times 2=14</math>

Revision as of 22:09, 28 February 2012

Problem

Bernardo and Silvia play the following game. An integer between $0$ and $999$, inclusive, is selected and given to Bernardo. Whenever Bernardo receives a number, he doubles it and passes the result to Silvia. Whenever Silvia receives a number, she adds $50$ to it and passes the result to Bernardo. The winner is the last person who produces a number less than $1000$. Let $N$ be the smallest initial number that results in a win for Bernardo. What is the sum of the digits of $N$?

$\textbf{(A)}\ 7\qquad\textbf{(B)}\ 8\qquad\textbf{(C)}\ 9\qquad\textbf{(D)}\ 10\qquad\textbf{(E)}\ 11$

Solution

Let's test each solution, for our first case $7$, we start out with $7$ and the number is then given to Bernardo. He will double the given number so in this case $7\times 2=14$