# Difference between revisions of "2012 AMC 10B Problems/Problem 4"

Line 4: | Line 4: | ||

<math> \textbf{(A)}\ 1\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 3\qquad\textbf{(D)}\ 4\qquad\textbf{(E)}\ 5 </math> | <math> \textbf{(A)}\ 1\qquad\textbf{(B)}\ 2\qquad\textbf{(C)}\ 3\qquad\textbf{(D)}\ 4\qquad\textbf{(E)}\ 5 </math> | ||

+ | |||

+ | |||

+ | == Solution == | ||

In total, there were <math>3+4=7</math> marbles left from both Ringo and Paul. <math>7/6</math>=1R1. <math>\text{This means that that there is}</math> <math> \boxed{1}</math> <math>\text{marbles left}</math> or | In total, there were <math>3+4=7</math> marbles left from both Ringo and Paul. <math>7/6</math>=1R1. <math>\text{This means that that there is}</math> <math> \boxed{1}</math> <math>\text{marbles left}</math> or | ||

− | + | <math> \textbf{(A)}</math> |

## Revision as of 22:27, 23 February 2012

## Problem 4

When Ringo places his marbles into bags with 6 marbles per bag, he has 4 marbles left over. When Paul does the same with his marbles, he has 3 marbles left over. Ringo and Paul pool their marbles and place them into as many bags as possible, with 6 marbles per bag. How many marbles will be left over?

## Solution

In total, there were marbles left from both Ringo and Paul. =1R1. or