Difference between revisions of "2012 AMC 10B Problems/Problem 5"

m (Solutions)
m (Solutions)
Line 18: Line 18:
 
<math>\frac{55}{2}*\frac{4}{5}=x</math>
 
<math>\frac{55}{2}*\frac{4}{5}=x</math>
  
<math>\boxed{x=22}</math>
+
<math>x=22</math>
  
'''OR'''
+
<math>\boxed{\textbf{(D)}}</math>
 
 
<math> \textbf{(D)}</math>
 
  
 
==See Also==
 
==See Also==

Revision as of 22:01, 23 February 2017

Problem 5

Anna enjoys dinner at a restaurant in Washington, D.C., where the sales tax on meals is 10%. She leaves a 15% tip on the price of her meal before the sales tax is added, and the tax is calculated on the pre-tip amount. She spends a total of 27.50 dollars for dinner. What is the cost of her dinner without tax or tip in dollars?

$\textbf{(A)}\ 18\qquad\textbf{(B)}\ 20\qquad\textbf{(C)}\ 21\qquad\textbf{(D)}\ 22\qquad\textbf{(E)}\ 24$


Solutions

Let x be the cost of her dinner.

$27.50=x+\frac{1}{10}*x+\frac{3}{20}*x$

$27+\frac{1}{2}=\frac{5}{4}*x$

$\frac{55}{2}=\frac{5}{4}x$

$\frac{55}{2}*\frac{4}{5}=x$

$x=22$

$\boxed{\textbf{(D)}}$

See Also

2012 AMC 10B (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
All AMC 10 Problems and Solutions

The problems on this page are copyrighted by the Mathematical Association of America's American Mathematics Competitions. AMC logo.png