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Difference between revisions of "2012 AMC 10B Problems/Problem 7"

(Solutions)
(Solutions)
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So by the info in the problem:
 
So by the info in the problem:
  
<math>\frac{x}{3}=(\frac{x}{4})+4</math>
+
<math>\frac{x}{3}=\left( \frac{x}{4} \right)+4</math>
 +
 
 +
Subtracting <math> \frac{x}{4}</math> from both sides leaves
 +
 
 
<math>\frac{x}{12}=4</math>
 
<math>\frac{x}{12}=4</math>
 +
 
<math>\boxed{x=48}</math>
 
<math>\boxed{x=48}</math>
  
 
This is answer choice <math>\textbf{(D)}</math>
 
This is answer choice <math>\textbf{(D)}</math>

Revision as of 17:49, 24 February 2012

Problem 7

For a science project, Sammy observed a chipmunk and a squirrel stashing acorns in holes. The chipmunk hid 3 acorns in each of the holes it dug. The squirrel hid 4 acorns in each of the holes it dug. They each hid the same number of acorns, although the squirrel needed 4 fewer holes. How many acorns did the chipmunk hide?

$\textbf{(A)}\ 30\qquad\textbf{(B)}\ 36\qquad\textbf{(C)}\ 42\qquad\textbf{(D)}\ 48\qquad\textbf{(E)}\ 54$


Solutions

Let $x$ be the number of acorns that both animals had.

So by the info in the problem:

$\frac{x}{3}=\left( \frac{x}{4} \right)+4$

Subtracting $\frac{x}{4}$ from both sides leaves

$\frac{x}{12}=4$

$\boxed{x=48}$

This is answer choice $\textbf{(D)}$

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